Question

How do you find the discriminant of 3x2+2x−1=0 and use it to determine if the equation has one, two real or two imaginary roots?

Answer 1

Answer:

Step-by-step explanation:

3x² + 2x - 1 = 0

À = 3 , b = 2 , c = -1

Discriminat = b² - 4ac

(2)² - 4×3 × -1

4 + 12 = 16

Answer 2

Given:

Use the discriminant to determine the number of real roots the equation has. 3x2 – 5x + 1 =0

Solution:

Discriminant = bx2 – 4ac

Compare the above equation 3x2 – 5x + 1 =0 with ax2 + bx + c = 0

We get, a = 3, b = -5, c = 1

Put the value of a, b and c;

Discriminant = bx2 – 4ac

Discriminant = (-5)2 - 4 × 3 × 1

= 25 – 12

= 13 [13 > 0]

Therefore, discriminant is positive.

So the given equation has two distinct real roots.

Answer =Two distinct real roots,