How do you find the discriminant of 3x2+2x−1=0 and use it to determine if the equation has one, two real or two imaginary roots?
Answers
Answered by
3
Answer:
Step-by-step explanation:
3x² + 2x - 1 = 0
À = 3 , b = 2 , c = -1
Discriminat = b² - 4ac
(2)² - 4×3 × -1
4 + 12 = 16
Answered by
1
Given:
Use the discriminant to determine the number of real roots the equation has. 3x2 – 5x + 1 =0
Solution:
Discriminant = bx2 – 4ac
Compare the above equation 3x2 – 5x + 1 =0 with ax2 + bx + c = 0
We get, a = 3, b = -5, c = 1
Put the value of a, b and c;
Discriminant = bx2 – 4ac
Discriminant = (-5)2 - 4 × 3 × 1
= 25 – 12
= 13 [13 > 0]
Therefore, discriminant is positive.
So the given equation has two distinct real roots.
Answer =Two distinct real roots,
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