Question

how do you find the n-factor of p2h4 in the given reaction: p2h4=ph3+p4h2

(EXPLAIN)

Answer 1

We have to find n - factor of P₂H₄ in the given reaction ; P₂H₄ ⇒PH₃ + P₄H₂

Solution : n - factor of a compound is number of electrons transferred from one mole of the compound.

So let's balance the chemical equation.

Step 1 : P₂H₄ + 2H⁺⇔2PH₃ - 2e¯......(1)

Step 2 : 2P₂H₄ ⇔P₄H₂ + 6H⁺ + 6e¯......(2)

multiplying 3 with eq (1)

3P₂H₄ + 6H⁺⇔6PH₃ - 6e¯......(1)

2P₂H₄ ⇔P₄H₂ + 6H⁺ + 6e¯ ......(2)

now if you add both equation you will get balance chemical equation. But here you should observe 6 electrons are transferred in each half reaction.

So, (3P₂H₄ + 2P₂H₄) transfer 6 electrons

⇒so, 1 P₂H₄ transfers 6/5 electrons.

Then, n - factor of P₂H₄ = 6/5