Question

How do you find the product (3b2−4b−7)(2b2−b−9)?

Answer 1

$(2b {}^{2} -b - 9 ) \times (3b {}^{2} - 4b - 7) \\ \\ 2b {}^{2} \times (3b {}^{2} - 4b - 7) - b \times(3b {}^{2} - 4b - 7) - 9 \times (3b {}^{2} - 4b - 7) \\ \\ 6b {}^{4} - 8b {}^{3} - 14b {}^{2} - 3b {}^{3 } + 4b {}^{2} + 7b - 27b {}^{2} + 36b + 63 \\ \\ = 6b {}^{4} - 11b {}^{3} - 37b {}^{2} + 43b + 63$

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