How do you find the slope of a line segment connecting points A(4,-5) and B(-5,8)?
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Answered by
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Solution:
Let A(4,-5) = (x1,y1)
B(-5,8) = (x2,y2)
Now ,
Slope of the line segment AB
(m) = (y2-y1)/(x2-x1)
= [8-(-5)]/[-5-4]
= (8+5)/(-9)
= -13/9
Therefore,
slope (m) = -13/9
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Answered by
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A(4,-5)=x1=4,y1=-5
B(-5,8)=x2=-5,y2=8
y2-y1/x2-x1
8-[-5]/-5-4
8+5/-9
-13/9
Therefore the slope of line is 13/-9
HOPE IT WILL HELP YOU FRIEND ✔✔
B(-5,8)=x2=-5,y2=8
y2-y1/x2-x1
8-[-5]/-5-4
8+5/-9
-13/9
Therefore the slope of line is 13/-9
HOPE IT WILL HELP YOU FRIEND ✔✔
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