How do you find the slope perpendicular to (-7,2) and (5,-12)?
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take slope of these coordinates
slope =y2-y1/x2-x1
slope =-12-2/5-(-7)=-14/12
perpendicular to these coordinates so
perpendicular =-1/slope
p =-1/-14/12=12/14
if am not wrong
take slope of these coordinates
slope =y2-y1/x2-x1
slope =-12-2/5-(-7)=-14/12
perpendicular to these coordinates so
perpendicular =-1/slope
p =-1/-14/12=12/14
if am not wrong
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