Question

How do you find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126?

Answer 1

let the numbers be x, x+1, x+2

sum of first and last term

2x + 3(x+2) = 126

2x + 3x + 6 = 126

5x + 6 =126

5x = 126 - 6

5x = 120

x = 120 ÷ 5

x = 24

the numbers are

x = 24, x+1 = 25, x +2 = 26

24, 25, 26