how do you reduce this to its lowest term?
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it can be written as (x²/3x )+ (-9/9)
cancel -9 with 9
=> (x × x /3× x )-1
cancel one of the x with the x in denominator
=> (x /3 )-1
cancel -9 with 9
=> (x × x /3× x )-1
cancel one of the x with the x in denominator
=> (x /3 )-1
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Answered by
1
x²-9=x²-3²
=(x+3)(x-3)
Therefore (x²-9)/3x+9=(x+3)(x-3)/3x+9
=(x+3)(x-3)/3(x+3)
(x+3) gets cancelled
(x²-9)/3x+9=(x-3)/3
=(x+3)(x-3)
Therefore (x²-9)/3x+9=(x+3)(x-3)/3x+9
=(x+3)(x-3)/3(x+3)
(x+3) gets cancelled
(x²-9)/3x+9=(x-3)/3
it is equal to (x/3)-3/3=(x/3)-1
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