If the radius of a current carrying conductor is halved how does the current change in the circuit?
Answers
Answered by
72
Resistance of a conductor wire
= R = Resistivity * Length/Area of cross-section
So if radius is halved, Area becomes1/4th and so resistance becomes 4 times.
So current becomes 1/4th, if the potential difference across the conductor remains same.
= R = Resistivity * Length/Area of cross-section
So if radius is halved, Area becomes1/4th and so resistance becomes 4 times.
So current becomes 1/4th, if the potential difference across the conductor remains same.
Answered by
11
if the conductor has zero resistance then the current does not change
if the resistance of the conductor is taken into account, then the resistance of the conductor will get 4 times as area becomes 1/4.
and if resistance of the conductor is the only resistance then the current becomes 1/4 the of its original value
if the resistance of the conductor is taken into account, then the resistance of the conductor will get 4 times as area becomes 1/4.
and if resistance of the conductor is the only resistance then the current becomes 1/4 the of its original value
Similar questions