Question

How do you say that maximum number of zeroes of x² + 8x + 15 is 2 ?​

Answer 1

Answer:

The order of polynomial x² + 8x + 15 is 2. Hence number of zeroes of it is 2.

The order of polynomial x² + 8x + 15 is 2. Hence number of zeroes of it is 2.Since the maximum possy zeroes of a polynomial is equal to its order.

                                        ANOTHER WAY ! ------

the highest degree of given polynomial is 2 so the maximum number of zeroes of given polynomial is 2

x^2 + 8x + 15 = 0

x^2 + 5x + 3x + 15= 0

x(X +5 ) + 3(X + 5) = 0

(X +5)(X+3) = 0

X = -5 and -3

Hence 2 zero of the given polynomial

Step-by-step explanation:

Answer 2

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How do you say that maximum number of zeroes of x² + 8x + 15 is 2 ?

$\huge\bold\purple{♡} {\orange{\underline{\pink{\mathbf{Solution}}}}} \bold\purple{♡}$

The order of polynomial x² + 8x + 15 is 2. Hence the maximum number of it is 2.

Since the maximum possible zeroes of a polynomial is equal to its order.