Question

The length of a rectangle is 5ft more than twice its width, and the area of the rectangle is 88ft. How do you find the dimensions of the rectangle?

Answer 1

hello mate here is your answer

Let x = the width

2x+5= the length

The equation is A=L*W

x(2x+5)=88

2x^2+5x-88=0

I hope this factors:

(2x-11)(x+8)=0

There appear to be two solutions:

2x-11=0 or x+8=0

2x=11 or x=-8 This answer is rejected since a side of a rectangle can't be negative.

x=11/2 or 5.5 ft = width

2x+5=Length

2(11/2)+5=11+5=16 = Length

Check: Area = L*W = 16*5.5 = 88sq ft.

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