Question

How do you solve 2x3+6x2–x–3=0?

Answer 1

2*3+6*2-x-3=0

6+12-x-3=0

6+12-3=x

18-3=x

X=15

Answer 2

Applying BODMAS rule : -

(2*3) + (6*2)-x-3 = 0

6 + 12 - x - 3 = 0

Transpose x to Right Hand Side

6 + 12 - 3 = x

Therefore x = 15.