How do you solve (−3i)(2i)(8+2i)?
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Solution:
/* We know , i² =-1 */
Now ,
(−3i)(2i)(8+2i)
= (-3×2)(i ² )(8+2i)
=(-6)(-1)(8+2i)
=6(8+2i)
Or
= 38+12i
••••
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