How do you solve 3x + 7 > 4x + 2?
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We know how to solve equation, We use the same method to solve inequations.
Given,
3x + 7 > 4x + 2
Add - 3x to both sides ;
3x + 7 - 3x > 4x + 2 - 3x
7 > x + 2
Add - 2 to both sides ;
7 - 2 > x + 2 - 2
5 > x
So, Any value of x less than 5 is the solution.
Therefore, Solution of 3x + 7 > 4x + 2 is x < 5.
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