Math, asked by vennelaboddeti9504, 1 year ago

How do you solve 4[2x−(3−x)+5]=−7x−2?

Answers

Answered by kanvar

0

4[2x-3+x+5]=-7x−2

4[3x+2]=−7x−2

12x+8=7x−2

5x=-10

x=-2

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