How do you solve 4(r+1)=6−2(1−2r)?
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4(r+1)=6-2(1-2r)
4r+4=6-2-4r
4r+4r=4-4
8r=0
r=0/8
therefore,r=0
Answered by
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=> 4 (r+1)=6-2 (1-2r)
=> 4r+4= 6-2+4r
=> 4r+4= 4r+4
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