How do you solve a(a+3)+a(a−6)+35=a(a−5)+a(a+7)?
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How do you solve a(a+3)+a(a−6)+35=a(a−5)+a(a+7)?
Answer:
a = 7
Step-by-step explanation:
a(a+3)+a(a−6)+35=a(a−5)+a(a+7)
simplify it first
a^2 + 3a + a^2 - 6a + 35 = a^2 - 5a + a^2 +7a
or, 2a^2 - 3a+35 = 2a^2 +2a
re-arranging terms
or , - 5a = -35
or, a = 7
Thank you .
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