Question

How do you solve equations with negative variables on both sides, fraction form? EXAMPLE: -12/3x + 14 = 29

Answer 1

Answer:

you can solve this by following example

Step-by-step explanation:

- 1/ x +- 2 = - 3 x

now , take - sign common

-( 1/ x + 2 ) = - ( 3x )

we have left ,

1/x + 2 = 3x

take 1/x to RHS, side

3x^2-1 = 2x

3x^2-2x -1 =0

3x(x-1) + 1( x-1)

(3x-1 ) (x-1 )

hence , we have two values of x as 1, 1/3