How do you solve the following system using substitution?: 5x+2y=−4,−3x+y=20
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Here is your answer
From equation 2,
-3x+y=20
y=20+3x......equation 3
Putting equation 3 in equation 2
5x+2(20+3x)=-4
5x+40+6x=-4
11x=-4-40
11x=-44
x=-44÷11
x=-4
Hope it helps you....
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