How do you solve the linear equations y=2x-3 and 4y=2x+8
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Subtract the first equation from the second to get:
4y-y=2x-2x+8+3
Simplifying, we see that 3y=11, so y=11/3. Substituting this into the first equation, we have:
11/3=2x-3
Adding 3, we see that 2x=20/3, so x=10/3.
4y-y=2x-2x+8+3
Simplifying, we see that 3y=11, so y=11/3. Substituting this into the first equation, we have:
11/3=2x-3
Adding 3, we see that 2x=20/3, so x=10/3.
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