How do you solve the system of equations 2x+3y=18 and 3x−5=y?
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Given:
2x+3y =18
and 3x-5 =y
2x+3 (3x-5) =18
or 2x+9x-15 =18
or 11x =18+15
or x = 33/11
: x = 3.
And,
3x-5 = y
or 3×3 -5 = y
or 9-5 = y
or y = 4.
Hence, x= 3 and y= 4.
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