Question

How do you solve the system x−4y=−8 and −3x+12y=24?

Answer 1

x-4y=-8 equation no.1

-3x+12y=24 equation no.2

equation no.1 multiply by-3

-3x+12y=24 equation no.3

add equation no.2 and 3

so, 24y=48

y=2

put the value of y in equation no.1

x-4(2)=-8

x-8=-8

x=0