Question

How do you solve x(x−12)+32=0?

Answer 1

Answer:

the answer is x=8,4

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Answer 2

x (x-12)+32

x^2-12x+32

x^2-8x-4x+32

x (x-8)-4 (x-8)

(x-8) (x-4)

x-8=0 x-4=0

x=8 x=4

Answer 3

x (x-12)+32

x^2-12x+32

x^2-8x-4x+32

x (x-8)-4 (x-8)

(x-8) (x-4)

x-8=0 x-4=0

x=8 x=4