How does drift velocity changes if we increase length 3 times but keep the electric field contant?
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1. The length of the weir is doubles but the cross sectional are of the wire is not changes ( 2 wires of same crooks sectional area and made up of the same material are connected end to end and the same potential difference is applied) - In this case the resistance of the wire increases 2 times. Since drift velocity of electrons is inversely proportional to the resistance of the wire, it becomes one half.
I = N×E×A×V
I=current
N= no. Density of electrons
A= area of cross section of the wire
V= drift velocity.
I is inversely proportional to R and thus V is also inversely proportional to R.
2. The length of the wire is doubled and thus cross section of the wire gets halved - In this case the resistance of the wire increases by 4 times and thus drift velocity becomes one fourth.
I think it is similar to u r answer
I = N×E×A×V
I=current
N= no. Density of electrons
A= area of cross section of the wire
V= drift velocity.
I is inversely proportional to R and thus V is also inversely proportional to R.
2. The length of the wire is doubled and thus cross section of the wire gets halved - In this case the resistance of the wire increases by 4 times and thus drift velocity becomes one fourth.
I think it is similar to u r answer
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