How does polarised dielectric modify the original external field inside it?
Answers
when a dielectric is placed an electric field is set up between the plates of the capacitor, in a direction opposite to the electric frield which was there before placing the dielectric.
due to this surface charge densities on the either sides of the plate is produced. the dielectric gets polarised due to induction and hence because of polarisation of the dielectric electric field is reduced overall.
Answer:
Explanation:
consider, for simplicity, a rectangular dielectric slab placed in a
uniform external field E0 parallel to two of its faces. The field
causes a uniform polarisation P of the dielectric. Thus every
volume element v of the slab has a dipole moment P v in the
direction of the field. The volume element v is macroscopically
small but contains a very large number of molecular dipoles.
Anywhere inside the dielectric, the volume element v has no net
charge (though it has net dipole moment). This is, because, the
positive charge of one dipole sits close to the negative charge of
the adjacent dipole.
However, at the surfaces of the dielectric normal to the electric
field, there is evidently a net charge density. As seen in Fig 2.23,
the positive ends of the dipoles remain unneutralised at the right
surface and the negative ends at the left surface. The unbalanced
charges are the induced charges due to the external field.
Thus, the polarised dielectric is equivalent to two charged
surfaces with induced surface charge densities, say p and –p.
Clearly, the field produced by these surface charges opposes the
external field. The total field in the dielectric is, thereby, reduced
from the case when no dielectric is present. We should note that
the surface charge density ±p arises from bound (not free charges) in the dielectric.