How does the acceleration due to 'g' varies at poles to equator? Show proper explaination.
Answers
Answered by
3
Acceleration due to gravity 'g' is maximum at polls because earth is flatter at the polls and minimum at equator because earth bulges out at the equator.
We know that 'g' increases when height from the surface of the earth decreases and decreases when height from the surface of the earth increases.
Hence 'g' is maximum at polls and minimum at equator.
Hope u like it...
We know that 'g' increases when height from the surface of the earth decreases and decreases when height from the surface of the earth increases.
Hence 'g' is maximum at polls and minimum at equator.
Hope u like it...
Saumyashrita3:
Mark it as brainliest plz !!!
Answered by
4
Due to the shape of Earth, the equator is bulged outwards whereas the poles lie nearer to the centre of earth as compared to the equatorial regions.
We also know that, g'= g[(r-h)/r]
=> g'∝ 1/r
that is, gravitational force is inversely proportional to distance from centre of earth.
Thus, acceleration due to gravity varies at poles to equator.
'g' at poles is more than that at equator due to less distance from the centre of earth.
We also know that, g'= g[(r-h)/r]
=> g'∝ 1/r
that is, gravitational force is inversely proportional to distance from centre of earth.
Thus, acceleration due to gravity varies at poles to equator.
'g' at poles is more than that at equator due to less distance from the centre of earth.
Similar questions
Computer Science,
8 months ago
Hindi,
1 year ago
Chemistry,
1 year ago
Science,
1 year ago
Physics,
1 year ago