How does the force of gravitation between two objects change when the distance between them is reduced to half ?
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HERE IS THE ANSWER ✌
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According to the law of gravitation , the force of attraction between any two objects of mass m1 and m2 is proportional to the product of their masses and inversely proportional to the square of the distance 'R' between them.
As given here F=Gm1×m2/R^2
Here G is the gravitational constant. When the distance (R) is reduced to half .
Then F′=Gm1×m2/R^2/2^2
Or F′=4F
Clearly, as the distance between the objects is reduced to half the force of gravitation becomes four times the original force.
✅✅✅✅✅✅
__________________
HOPE IT HELPS ☺☺☺
HERE IS THE ANSWER ✌
___________________
According to the law of gravitation , the force of attraction between any two objects of mass m1 and m2 is proportional to the product of their masses and inversely proportional to the square of the distance 'R' between them.
As given here F=Gm1×m2/R^2
Here G is the gravitational constant. When the distance (R) is reduced to half .
Then F′=Gm1×m2/R^2/2^2
Or F′=4F
Clearly, as the distance between the objects is reduced to half the force of gravitation becomes four times the original force.
✅✅✅✅✅✅
__________________
HOPE IT HELPS ☺☺☺
ShraddhaRajput:
hey
Answered by
1
Dear Student,
◆ Answer -
Gravitational force is quadrupled when distance between objects is halved.
● Explanation -
Gravitational force acting on the bodies is given by -
F = Gm1m2 / r^2
When distance is halved, gravitational force is given by -
F' = Gm1m2 / r'^2
F' = Gm1m2 / (r/2)^2
F' = 4Gm1m2 / r^2
F' = 4F
Therefore, gravitational force will become 4 times the previous.
Thanks dear. Hope this helps you..
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