How does the k.E. Of a body changes when it's linear momentum is doubled?
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Hey there,
p=mv, and
KE=mv²/2
where p is momentum and KE is kinetic energy.
So KE=p²/2m
p=√(2mKE)
If KE is doubled, then p=√(2m2KE)
So the momentum becomes √2 times.
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