HOW DOES THE KINETIC ENERGY OF A BODY CHANGE IF ITS MOMENTUM IS DOUBLED ?
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Answered by
7
K E=1/2 mv²
momentum ,P=mv
K E = 1/2 Pv
if momentum is doubled, P=2P
so, KE=1/2 .2P.v
KE=Pv
kinetic energy is 1/2 times increased
momentum ,P=mv
K E = 1/2 Pv
if momentum is doubled, P=2P
so, KE=1/2 .2P.v
KE=Pv
kinetic energy is 1/2 times increased
Answered by
1
See attachment dear mate
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