how does the lateral displacement depend upon the angle of incidence
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Here's the answer to your question...
→Yes it does
By using elementary geomety, it can be proved that
d1d2=cosicosrd1d2=cosicosr
where d1d1 and d2d2 are the width of the light beam in the incident and refracted medium respectively, and
ii and rr are the incident and refracted angle respectively
Lateral Shift would be ∣d1−d2∣
Here's the answer to your question...
→Yes it does
By using elementary geomety, it can be proved that
d1d2=cosicosrd1d2=cosicosr
where d1d1 and d2d2 are the width of the light beam in the incident and refracted medium respectively, and
ii and rr are the incident and refracted angle respectively
Lateral Shift would be ∣d1−d2∣
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