How does the magnetic flux passing through the circular loop change?
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the loop is assumed to be an ideal thin wire, the cross sectional area tends to zero. Also, since there is negligible amount of length for emf to be induced, there is no flux linkage with the loop and therefore any change in current through the wire produces mo effect on the wire or emf.
The magnetic field is perpendicular to the current's direction, and the current is going normal to the loop, meaning that BBis parallel to the loop's plane. Because flux is the dot product of the magnetic field and the loop's normal "surface vector", and the angle is 90∘90∘, it is equal to 00, thus not changing in time and not inducing an emf.
ε=−dΦdt=−ddt(0)=0
The magnetic field is perpendicular to the current's direction, and the current is going normal to the loop, meaning that BBis parallel to the loop's plane. Because flux is the dot product of the magnetic field and the loop's normal "surface vector", and the angle is 90∘90∘, it is equal to 00, thus not changing in time and not inducing an emf.
ε=−dΦdt=−ddt(0)=0
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