How does the second law of motion show relation of momentum with force?
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Second law states that
F=ma.....
Since a = (v-u)/t....
F becomes m× (v-u)/t
= mv-mu/t....
mv and mu are final and initial momentum
Therefore force is rate of change of momentum...
F=ma.....
Since a = (v-u)/t....
F becomes m× (v-u)/t
= mv-mu/t....
mv and mu are final and initial momentum
Therefore force is rate of change of momentum...
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