How does the velocity- time graph for uniform motion helps to calculate the displacement covered during a given time t?
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In velocity Time graph , Time is taken along X axis and velocity on Y axis....
Consider the graph :
The graph for uniform motion will be straight parallel to Time axis.
Let A and B be two points at time T1 and T2
Since motion is uniform: AA1=BB1= V
Area under Velocity time graph =AA1xA1B1=V(T2-T1)-------------(1)
Velocity= V=displacement/time=x2-x1/t2-t1
V(T2-T1)=x2-x1
Area ABB1A1=X2-X1
Hence displacement of a particle is equal to the area under velocity time graph
Consider the graph :
The graph for uniform motion will be straight parallel to Time axis.
Let A and B be two points at time T1 and T2
Since motion is uniform: AA1=BB1= V
Area under Velocity time graph =AA1xA1B1=V(T2-T1)-------------(1)
Velocity= V=displacement/time=x2-x1/t2-t1
V(T2-T1)=x2-x1
Area ABB1A1=X2-X1
Hence displacement of a particle is equal to the area under velocity time graph
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abhi178:
awesome answer mam , thanks for answering
Answered by
10
Displacement is area under velocity time graph.
Since velocity time graph for uniform motion is parallel to x axis or time axis.
Hence displacement under velocity time graph for uniform motion is equal to area of rectangle.
Means velocity unit (x ms-1) * time (y s) = xy m.
Hope it's helpful to u.
Since velocity time graph for uniform motion is parallel to x axis or time axis.
Hence displacement under velocity time graph for uniform motion is equal to area of rectangle.
Means velocity unit (x ms-1) * time (y s) = xy m.
Hope it's helpful to u.
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