Physics, asked by neha6153, 1 year ago

how far the two electrons be placed so that force of repulsion is equal to the weight of electron?

Answers

Answered by QuestionSlayer

2

ke^2/r^2=mg

where e = 1.6*10^-19 C
m =9.1 * 10^-31 kg

Previous Question

Next Question

Similar questions

English, 7 months ago

we_be rewaeded(fill in the blanks with appropriate madals)...

Social Sciences, 7 months ago

Q.4 Imagine our Earth takes a Sunday off like we have, then what would happen? Explain how it would affect us.

Physics, 7 months ago

what is the unit of pressure....?

English, 1 year ago

she seemed to find nothing stage...

Math, 1 year ago

mean age of 25 students of a club was 38 years if five members with mean age of 42 years have left the club , what is the present mean age of the club member...

Math, 1 year ago

prove that cosA-sinA+1/cosA+sinA-1= cosecA+cotA...

Math, 1 year ago

A lady bought 8 pencil ,5eraser for rupee 21 to give 5children but when she visit there were 9children. She bought 3 pencil and 4 eraser for rupee 10 find the price of one pencil and one eraser...

History, 1 year ago

write short note on kalinga war. (10 mark question, very important)...