how far would the body travel if it accelerated for 5sec and the initial velocity of 2m/sec
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Answer:
62.5 metre far apart from its original position.Using v=u +at ,by putting u=0,v=2 m/sec and t=5,we calculate for a.Then using s=ut+1/2at×t, we calculate for Sand finally we got the answer
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As we have 2nd eqn of motion.
S= ut+1/2at^2
S= 2 *5 +a/2 *25
S= 10+ a/2 * 25
If acceleration is given we can finds it exact value, or if the motion is in vertical direction we can calculate its value by taking value of g ie. 9.8
.......mark it as brainliest..........
S= ut+1/2at^2
S= 2 *5 +a/2 *25
S= 10+ a/2 * 25
If acceleration is given we can finds it exact value, or if the motion is in vertical direction we can calculate its value by taking value of g ie. 9.8
.......mark it as brainliest..........
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