Question

How fast does a man , weighing 60 kg , run so that his kinetic energy is 750 joule solve the numericale?

Answer 1

here, mass m = 60kg , kinetic energy=750
but, kinetic energy=1/2mv^2
hence, 1/2mv^2=750
60×v^2=750×2
v^2=1500/60
v^2=25
v = 5m/s

Answer 2

• Mass = 60 kg

• K.E = 750 J

• v = ?

→ K.E = (1/2)mv²

⇒ 750 = (1/2) × 60 × v²

⇒ v² = 150/6

⇒ v = √25

⇒ v = 5 m/s

∴  The man should run with a velocity of 5m/s