How fast does a man weighing 60 kg run so that his kinetic energy is 750 joule ?
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Answered by
11
Given ;
Mass = 60 kg
K.E = 750 J
v = ?
K.E = (1/2)mv^2
750 = (1/2) × 60 × v^2
v^2 = 150/6
v = √25
v = 5 m/s
____________________
Hence the man should run with a velocity of 5m/s
Mass = 60 kg
K.E = 750 J
v = ?
K.E = (1/2)mv^2
750 = (1/2) × 60 × v^2
v^2 = 150/6
v = √25
v = 5 m/s
____________________
Hence the man should run with a velocity of 5m/s
santoshsinghs9473:
Thanks Adarsh
Answered by
2
let the velocity of man is v
then, 1/260v^2=750
=>30v^2=750
=>v^2=25
=>v=5m/s
then, 1/260v^2=750
=>30v^2=750
=>v^2=25
=>v=5m/s
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