Question

how fast should a man begging 600 Newton Run so that his kinetic energy is 750 Joule? (g = 10m/sec²)

Answer 1

Given ;

Mass =600N=60 kg

K.E = 750 J

v = ?

K.E = (1/2)mv^2

750 = (1/2) × 60 × v^2

v^2 = 150/6

v = √25

v = 5 m/s

Answer 2

ANSWERS :-

SOLUTION ,

Given,

W = 600N

g = 10m/sec²

kinetic energy = 750 J

V = ?

now,

W = mg

600N = m * 10

m = 600/10

m = 60 kg


kinetic energy = 1/2 mv²

750 = 1/2 * 60 * v²

so,

v² = 2 * 750/60

v² = 25

v = √25

v = 5 m/sec

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