Question

how fast should a man of Mass 60kg run so that his kinetic energy is 750J

Answer 1

Given ;

Mass = 60 kg
K.E = 750 J
v = ?

K.E = (1/2)mv^2

750 = (1/2) × 60 × v^2
v^2 = 150/6
v = √25
v = 5 m/s
____________________
Hence the man should run with a velocity of 5m/s

Answer 2

The man must run with a velocity of 5m/s so that his kinetic energy is 750 J.

Given,

Mass of the man = 60kg.

Kinetic Energy possessed by the man = 750J.

To find,

How fast should a man run so that his kinetic energy is 750J?

Solution,

• Kinetic energy can be defined as the energy possessed by any moving body.

• Kinetic energy is represented as K.E and its formula is K.E = (1/2)mv².

• Kinetic Energy is measured in Joules.

K.E = 750J

m = 60kg.

Putting, these values into the formula of K.E.

⇒   K.E = (1/2)mv².

⇒   750 = (1/2)60v².

⇒   1500 = 60v².

⇒   v²= 1500/60

⇒   v²= 25m/s.

⇒   v = 5m/s.

Hence, the man must run with a velocity of 5m/s so that his kinetic energy is 750 J.