Question

How fast should a rocket move for its length to be contracted to 50% of its rest length

Answer 1

❧Hi my dear friend,

We will apply special relativity here,

γ = 1/√(1–V²/c²)

so, here, γ= original length / length after contraction=1/0.99

=> 1/0.99=1/√(1–V²/c²)

1–V²/c²=0.9801

V²/c²=0.0199

V/c=0.141

=141/100= (14.1%)c

~Thank you☙

Answer 2

Heyya here u go :-

1sec=11.2km

hope it helps :)