Question

How find second cost when two ration given and sigle share cost?

Answer 1

Hey there,

Your answer.

$= > let \: the \: second \: cost \: be \: x \\ \\ = > single \: cost \: is \: x \: \\ \\ = > and \: ratio \: is \: \: x:x \\ \\ = > to \: find \: the \: second \: cost \: i f\:ratio \\ and \: single \: cost \: is \: given \: we \: have \: to \\ take \: ratio \: first \: and \: then \: mark \: the \: \\ sign \: of \: :: \: ( \: proportion \: )then \: take \: the \: \\ second \: cost \: ( \: x \: ) \\ \\ = > you \: can \: write \: it \: as \: follow. \: \\ \\ = > \: x:x \: ( \: ratio \: ):: \: single \: cost \: : \: second \: cost$

Example,

-》There, costs are in ratio 2:5 and the single cost is 10, then find the second cost?

Answer-》Let the second cost be x

-》Given, the ratios are 2 : 5 and single cost is 10

-》Then, 2 : 5 : : 10 : x

-》Multiply the extreme terms and middle terms.

-》2 × x = 5 × 10

-》2x = 50

-》x = 50/2

-》25

:-) Hope it helps !