Question

how fo solve equations
16/a^2 +9/b^2=1 and
1/a^2+16/b^2​

Answer 1

Answer:

The second equation is incomplete

Replace 1/a^2 with x and 1/b^2 with y

Then solve it

Hope it will help you

Answer 2

Answer:

hi buddy

Step-by-step explanation:

Just make variable changes; let:

{ = 1/²

{ = 1/²

Your system becomes:

{ 16 + 9 = 1

{ 36 + 4 = 1

Multiply first equation by 4 and second by 9:

{ 64 + 36 = 4

{ 324 + 36 = 9

Subtracting last equation from first one:

(324 + 36) – (64 + 36) = 9 – 4

324 – 64 + 36 – 36 = 5

260 = 5

52 = 1

= 1/52

Then from first equation:

16 + 9 = 1

16/52 + 9 = 1

9 = 1 – 16/52

9 = 1 – 4/13

9 = (13 – 4)/13

9 = 9/13

= 1/13

Thus:

{ = 1/52

{ = 1/13

and:

{ ² = 1/ = 52 = (2√13)²

{ ² = 1/ = 13 = (√13)²

Thus there are four solutions to your initial system:

(; ) = (-2√13; -√13)

(; ) = (-2√13; √13)

(; ) = (2√13; -√13)

(; ) = (2√13; √13)

hope it helps ya

if there is a change in value from question to answer then pls change it, it's my keyboard problem. but the method is same.

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