Question

HOW HENRY LAW IS A SPECIAL CASE OF RAOULTS LAW ?

Answer 1

Answer:

At a given temperature liquids vaporize. At equilibrium the pressure exertedby the vapour of the liquid over the liquidphase is referred to as vapour pressure.

According to Raoult’s law, vapour pressure of a volatile component in a given solution ca be defined by pi = pi 0 xi

In an answer of a gas in a fluid one of the segments is volatile to the point that it exists as a gas and solvency is given by Henry's law which expresses that p = KH x

Comparing both the equations we get that partial pressure of the volatile component or gas is directly proportional to its mole fraction in solution. Proportionality constant KH differs from p10

Therefore, Raoult's law turns into a unique instance of Henry’s law in which KH get to be equivalent to p10.