Question

How i calculate the value of the sum 2n+3n! ?

Answer 1

as I know that n! =n×(n-1)×(n-2)×......3×2×1
so,
2n+3n!
=n{2+3(n-1)!} =n[2+3{(n-1)×(n-2)×.....×3×2×1}]

Above this process we evaluate the value of (2n+3n!)