Question

HOW IS 1+3+5+...+(2k +1) +(2k-1)=
${k}^{2} + 2k + 1$
​

Answer 1

Answer:

Correct option is

B

3

k,2k−1,2k+1 are three terms in A.P. Then,

Common difference between first two terms = 2k−1−k =k−1

Common difference between next two terms = 2k+1−2k+1 =2

The common difference between consecutive terms should be equal.

Hence, k−1=2

k=3

Step-by-step explanation:

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