how is 2Cr(OH)4- + 3H2O2 + 2OH- →2CrO42- + 8H2O more simplified, making CrO42- a reactant, H2O2 cause a redox reaction. Dissolve one substance but not the other?
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Explanation:
In the ion-electron method (also called the half-reaction method), the redox equation is separated into two half-equations - one for oxidation and one for reduction. Each of these half-reactions is balanced separately and then combined to give the balanced redox equation.
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