How is cot²A(secA-1)/(1+sinA) ={(cos²A/sin²A)(1/cosA-1)}/(1+sinA)?
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Answer:
taking LHS
Cot^2A(secA-1)/(1+sinA)
sin^2A/cos^2A(1/cosA-1)/(1+sinA)
- cot^2A=cos^2A/sin^2A
- secA=1/cosA
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