Math, asked by shoryakhatri7, 1 year ago

How is cot²A(secA-1)/(1+sinA) ={(cos²A/sin²A)(1/cosA-1)}/(1+sinA)?

Answers

Answered by masterchouhan

1

Answer:

taking LHS

Cot^2A(secA-1)/(1+sinA)

sin^2A/cos^2A(1/cosA-1)/(1+sinA)

cot^2A=cos^2A/sin^2A
secA=1/cosA

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