Chemistry, asked by kshitiz53, 10 months ago

How is flourine-18 a radioactive element???​

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Answered by pragok
0

Answer:

Fluorine-18 (18F) is a fluorine radioisotope which is an important source of positrons. It has a mass of 18.0009380(6) u and its half-life is 109.771(20) minutes. It decays by positron emission 97% of the time and electron capture 3% of the time. Both modes of decay yield stable oxygen-18.

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