How is hydrogen ion concentration decreases when water is poured in concentrated acid?
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Suppose an acid filled half in a container of capacity 1 liter has 10−310−3 moles of H+ ions. The concentration of H+ ions is 22x10−310−3(Formula of calculating Concentration is
Concentration of Solution =No. of particles/ Volume)
Concentration of our solution = 10−3/0.510−3/0.5 liter
= 22x10−310−3 Molar ( Concentration is equal to 1 Molar is when 1 mole of any substance is dissolved in 1 liter)
If we fill the container fully with pure water. The no. of H+ ions that were spread over half the container, now spread in the container that is fully filled. So, by imagination, we can imagine that now the distance between one H+ and another H+ is now more than before. So, no. of H+ ions in a given volume is now less than before.
I can also prove it by calculation.
Concentration of our solution now = 10−3/110−3/1liter
=10−310−3 Molar
Hope U Understand
Concentration of Solution =No. of particles/ Volume)
Concentration of our solution = 10−3/0.510−3/0.5 liter
= 22x10−310−3 Molar ( Concentration is equal to 1 Molar is when 1 mole of any substance is dissolved in 1 liter)
If we fill the container fully with pure water. The no. of H+ ions that were spread over half the container, now spread in the container that is fully filled. So, by imagination, we can imagine that now the distance between one H+ and another H+ is now more than before. So, no. of H+ ions in a given volume is now less than before.
I can also prove it by calculation.
Concentration of our solution now = 10−3/110−3/1liter
=10−310−3 Molar
Hope U Understand
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