Math, asked by rajibsarma1967, 4 months ago

How is it done ? Explain please​

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Answered by kushagrapatil
0

Answer:

divisibility by 9 requires the sum of digits divisible by 9 , by 4 it requires last two digits be zero or divisible by 4 and for three the sum of all digits to be divisible by three

Answered by RealSweetie
2

Answer:

  1. because the sum of the digits of the number is divisible by 9
  2. 2 is a factor of 4
  3. because the eum if digits of the number is divisible by 3

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