How is it done ? Explain please
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divisibility by 9 requires the sum of digits divisible by 9 , by 4 it requires last two digits be zero or divisible by 4 and for three the sum of all digits to be divisible by three
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- because the sum of the digits of the number is divisible by 9
- 2 is a factor of 4
- because the eum if digits of the number is divisible by 3
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