Question

How is potential drop related to resistance when resistors are connected in series?

Answer 1

We can roughly say that if a no. Of resistors say 2 of equal resistance is connected in series then R equivalent will be greater (than compared than the individual resistors or if they r connected in parallel).....
Therefore as our R increases (keeping I constant) then our V will also increase.... I=V/R
I'm giving examples in attachment so that it clears all the doubts....

Answer 2

Answer:

Consider two resistances R1 and R2 connected in series with a battery having potential difference .Since in series combination current remains same.Let be the current in the circuit.

The equivalent resistance of the circuit,Rs = R1 + R2

V = IRs = I(R1 + R2)

= IR1 + IR2

V = V1 + V2

It means potential of battery is divided between the resistances in series in the circuit.